How do I proof this theorem?? (x)(y)(z)((x=y&y=z)→x=z)
I have tried using RAA at first ~(x)(y)(z)((x=y&y=z)→x=z)
and I got ~(a=b&b=c)→a=c) after using QN and EI
then I used MI to get ~(~(a=b&b=c)v a=c)
Then I used DeM to get (~~(a=b&b=c) & ~(a=c)
At the end I have a=b, b=c and ~(a=c)
I think I need to proof that a=c to complete RAA but I don't know how to or what law to use.