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I need a quick check on my homework to see if any questions are wrong. We just finished learning quantifiers (for all, for every) today and the assignment is due tomorrow.

enter image description here

My answers:

(a) Lr ∧ Lb
(b) ¬Dr
(c) Db ↔ Dm
(d) Lc ∧ ¬Dc
(e) Bvk ∧ Bak
(f) ∃x(Lx ∧ ¬Dx)
(g) (La ∧ Da) → (Lc ∧ ¬Dc)
(h) Bck

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  • I may not be an expert in logics, but looks just fine.
    – Philip Klöcking
    Nov 9, 2016 at 5:15
  • g and h are wrong. The error in h is insignificant. h should (Dc v ~Dc) -> Bck. g is backwards -- "only if" makes what follows "only if" the antecedent.
    – virmaior
    Nov 9, 2016 at 5:42
  • @virmaior h) My Professor said that "whether or not" is a dummy operative, and there was an example he gave that didn't have the "whether or not" symbolized. g) My Professor said today that "only if" governs the consequent. Is that equivalent to what you said?
    – K.Wong
    Nov 9, 2016 at 5:50
  • @virmaior: As I had to look it up myself - 'p only if q' means that if p happened, q is implied, because without it, p wouldn't have happened (necessary condition). Whereas 'p if q' exactly means q -> p, because it means "if q, then p". Therefore, I'd argue that G is correct. Regarding (h) it comes down to conventions I guess. Writing out tautologies and crossing them out afterwards may help showing that you understood what you're doing, but if the teacher does not like it, it's better not to do it.
    – Philip Klöcking
    Nov 9, 2016 at 6:34
  • 2
    Regarding the "dummy operator", it makes sense. If we introduce (as suggested) the "dummy" antecedent (Dc v ~Dc), due to the fact that it is always TRUE, the truth-value of the conditional (Dc v ~Dc) → Bck will be the same of Bck. Nov 9, 2016 at 7:25

1 Answer 1

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As has been pointed out, h is debatable but the rest is correct. Also note that the definition of B is ambiguous, since it doesn't differentiate between the two underscores: does Bab mean that a is better than b or that b is better than a?

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  • Regarding the latter: It is quite explicitely defined: B_ _ means _ is a better logician than _ - so the first token is better than the second. I do not see any ambiguity here.
    – Philip Klöcking
    Nov 9, 2016 at 16:09
  • @PhilipKlöcking I don't see a difference between the two underscores, so I would prefer normal variables.
    – user2953
    Nov 9, 2016 at 16:11

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