Just as the question proposes, I'm having trouble with proving this tautology. I know one should use proof by contradiction however I am currently stuck.

  • 1
    Assume (P↔¬P) and derive a contradiction. Mar 5 '18 at 7:07
  • 1
    Second step: unpack P↔¬P with -elimination rule. Mar 5 '18 at 10:13

Here is a proof using the Fitch software:

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