Q ∧ S
(Q ∧ ¬P) → ¬R
Q → ¬P
(S ∧ T) → (P ∨ R)
The goal is:¬T
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Sign up to join this communityDerive a contradiction under the assumption of T
, so that you may deduce ¬T
by negation introduction.
| Q ∧ S
| (Q ∧ ¬P) → ¬R
| Q → ¬P
|_ (S ∧ T) → (P ∨ R)
| S ∧ E
| Q ∧ E
: :
| |_ T
| | S ∧ T ∧ I
| | P ∨ R → E
: : :
| | #
| ¬T ¬ I