Your attempted application of Existential Elimination rule is incorrect. It takes the following form.
| m. Ǝx Px
| |_n. [a] Pa Assume a witness
| | :
| | p. R Derive a statement not containing the witness variable (a)
| q. R m,n-p Existential Elimination
The contradiction constant is a statement not containing any variables, so would be valid to use here; if you can somehow derive it.
Your attempted proof is to assume Ǝx Ǝy Sxy
aiming is to derive a contradiction under this context, so you can then use negation introduction.
Well, in between, you have three existences to eliminate; two in that assumption and one in the premises. So raise three assumptions of witnesses, derive the contradiction, then discharge back to the first context, and so finish.
| Ɐx Ɐy (Sxy → ¬Qxy) S : Smaller
|_ Ǝx Ɐy Qxy Q : SameSize
| |_ Ǝx Ǝy Sxy
| | |_ [a] Ɐy Qay Assume witness [a]
| | | |_ [b] Ǝy Sby Assume witness [b]
| | | | |_ [c] Sbc Assume witness [c]
| | | | | Ɐy (Sby → ¬Qby) Universal Elimination
| | | | | Sbc → ¬Qbc Universal Elimination
| | | | | ¬Qbc Conditional Elimination
| | | | | :
| | | | | :
| | | | | :
| | | | | Qbc Somehow
| | | | | ┴ Negation Elimination
| | | | ┴ Existential Elimination [c]
| | | ┴ Existential Elimination [b]
| | ┴ Existential Elimination [a]
| ¬Ǝx Ǝy Sxy Negation Introduction
Now... all you need is to derive Qbc
. However, there is no valid way to do so... unless you have access to Analytic Consequences regarding SameSize
. After all, the second premise says "There is a thing that is the same size as everything."
Such as...
Ɐx Qxx Reflexivity
Ɐx Ɐy (Qxy → Qyx) Symmetry
Ɐx Ɐy Ɐz (Qxy → (Qyz → Qxz)) Transitivity
If so, then put them to good use.